A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do I solve this equation:
(2x)^2=x^2+36^2?
anonymous
 5 years ago
How do I solve this equation: (2x)^2=x^2+36^2?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Meh, I just did the whole thing, but server crashed.. :P Oh well, I'll do it again. (2x)^2 = 4x^2 So you got 4x^2 = x^2+36^2 By subtracting x^2 on both sides you get: 3x^2 = 36^2 Take your calculator, and do 36^2, you'll get 1296 You now have: 3x^2 = 1296 Divide both sides by 3 gives: x^2 = 432 Which gives \[x = + \sqrt{}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ofcourse the server bugs again... Continuing where it failed: Which gives: x = + squareroot of 432
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.