Solve for x: (9/7)log base 2 of x = -9

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Solve for x: (9/7)log base 2 of x = -9

Mathematics
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First get the log function by itself: \[\frac {7}{9}*\frac {9}{7} *\log_{2}(x)=\frac{-9}{1}*\frac {7}{9}\]
i got it. the answer is 1/128
Good. Out of curiousity did you use a calculator or convert to base ten logs first?

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Since the problem can be translated to \[\log_{2} x^{9/7}=9\]. I changed it to exponential form and got \[2^{9} = x^{9/7}\]
then i got rid of the exponents by raising them to the reciprocal of that 9/7 and got (2^-7)=x and simplified
Very nice - I like your method more. :-)
Thank you.
Just as it should be solved, exploit those log rules!! ;)

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