anonymous
  • anonymous
how to integrate x squared - x cube dx with a limit from 0 to 1?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\int\limits_{}^{}x^2-x^3dx\] yes?
anonymous
  • anonymous
Woops forgot to put in the limits of integration. My bad.
anonymous
  • anonymous
Anyways, remember that you can integrate two functions which are added/subtracted by first finding the integral of each, then adding/subtracting them (by the same token as differentiation of the sum/difference of two fxns) First, split this into two different integrals, then solve each. Piece them back together, and you'll have your F(x). After that, don't forget to plug in your limits of integration. Your answer should be \[F(x) = x^3/3 - x^4/4\] from 0 to 1 1/3 - 1/4 = 1/12

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
sorry, my fault.. its actually square root of x - x cube..
anonymous
  • anonymous
OK so it's \[\int\limits_{0}^{1} \sqrt{x-x^3}\]
anonymous
  • anonymous
only the first x has the square root :c
anonymous
  • anonymous
Oh ok that makes sense haha. I was scratching my head. Same deal though! Integrate each one separately then calculate each against the limits of integration.
anonymous
  • anonymous
wait, ill do it :D
anonymous
  • anonymous
\[\int\limits_{}^{} \sqrt{x} = (2x^{3/2})/3\] and \[\int\limits_{}^{}x^3 = x^4/4\] Combine the functions, take your limits of integration, and solve! Gotta get to bed though, good luck on this problem. If you still aren't getting it right, keep at it, there will be someone around to help ya ;)
anonymous
  • anonymous
thanks for the help dude :D, actually im just on the first step.. hehehe.. im doing to find the center of the mass.. hehehe
anonymous
  • anonymous
No problem! Good luck with the rest of the problem, but by now I'm sure it's been long since you solved it!

Looking for something else?

Not the answer you are looking for? Search for more explanations.