anonymous
  • anonymous
Hi there, i was wondering if you could help me find the range of this function: 3ln(y + 4) = 2ln(x + 2) -2ln(x + 9) + 3ln(x^2 -1)
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
(range of values for x and y)
anonymous
  • anonymous
hello
anonymous
  • anonymous
ok we see that we have ln (y+4) on the left side. so y+4 > 0 , since ln 0 or ln (negative) is not defined. so y > -4 for the range. for the domain we have x + 2 > 0 , x + 9 > 0 and x^2 -1 > 0 you take the intersection of these conditions. so x > -2 , x > -9, x > 1 or x < -1 . so the domain is (-2, -1) union (-1, oo)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
please check work over
anonymous
  • anonymous
Thank you very much for your reply. i spent the whole day looking at it and i couldnt get my head around it. i was trying to gather the terms on the right hand side to simplify the function. guess i was looking at it the wrong way!

Looking for something else?

Not the answer you are looking for? Search for more explanations.