just checking over solution for question:
A tract of land bordered by a highway along the y-axis, a dirt road along the x-axis, and a river whose path is given by the equation y=4-0.2x^2, where x and y are in hindreds of meters.
The tract is 300m deep along the dirt road The value of the land is constant in any strip parallel to the highway and increases as you move way from the highway, with the value given by v=1000+50x dollars per 10,000 m^2 at the sample point (x,y). Find dW, the worth of a strip. Write an integral that equals the worth of the entire tract.
Stacey Warren - Expert brainly.com
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here is my solution. we have integral dw, where dw is a strip of the "worth" of the land.
The dw is like Area(x)*value(x) at x as you go along , but Area(x) is y(x)*dx
so integral (4 - .2x^2) ( 1000 + 50x) dx from 0 to 3