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anonymous 5 years ago Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 2 m/s. How fast is the area of the spill increasing when the radius is 19 m?

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1. bahrom7893

This is a very simple problem: $A=\pi r^2$ And you know that the change in radius dr/dt = 2 m/s

2. bahrom7893

Now you have to find out what dA/dt is, when r = 19m To find this, take the derivative of Area: dA/dt = 2*pi*r*(dr/dt)

3. bahrom7893

You need to know what is the change in area when r =19m and dr/dt = 2m/s so plug those values in: dA/dt = 2pi * 19m * 2m/s dA/dt = 76*pi (m^2/s) <=Your answer

4. anonymous

looks good , i concur

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