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anonymous

  • 5 years ago

Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 2 m/s. How fast is the area of the spill increasing when the radius is 19 m?

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  1. bahrom7893
    • 5 years ago
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    This is a very simple problem: \[A=\pi r^2\] And you know that the change in radius dr/dt = 2 m/s

  2. bahrom7893
    • 5 years ago
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    Now you have to find out what dA/dt is, when r = 19m To find this, take the derivative of Area: dA/dt = 2*pi*r*(dr/dt)

  3. bahrom7893
    • 5 years ago
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    You need to know what is the change in area when r =19m and dr/dt = 2m/s so plug those values in: dA/dt = 2pi * 19m * 2m/s dA/dt = 76*pi (m^2/s) <=Your answer

  4. anonymous
    • 5 years ago
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    looks good , i concur

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