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anonymous
 5 years ago
Algebra 2
Scott launches a model rocket from ground level. The rocket's height h in meters is given by the equation h = 4.9t sq + 56t, where t is the time in seconds after the launch.
a) what is the maxium height the rocket will reach?
b) how long after it is launched will the rocket reach its maxium height?
c) Scott stands on a stool that is 3 meters off the ground to launch the rocket, what is the new height equation? What is the new max height?
anonymous
 5 years ago
Algebra 2 Scott launches a model rocket from ground level. The rocket's height h in meters is given by the equation h = 4.9t sq + 56t, where t is the time in seconds after the launch. a) what is the maxium height the rocket will reach? b) how long after it is launched will the rocket reach its maxium height? c) Scott stands on a stool that is 3 meters off the ground to launch the rocket, what is the new height equation? What is the new max height?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey is this a calc/derivative problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or are you supposed to be solving it in a different way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can do this with the first derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to know when the rate of change of the height is zero, so you take the first derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. h = 4.9t^2 + 56t 2. dh/dt = 4.9*2*t + 56

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there will be a maximum when that rate is zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 560/98 = 280/49 = 40/7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so at 40/7 seconds, it will reach its highest point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 40/7 seconds is the correct answer for (B). if you put that back into original height equation, you will have the answer to A.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer to C is just 3 meters plus the answer to A

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since the rocket still peaks after the same amount of time  just three meters higher

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me know if you were supposed to do this in a different way (eg. graphing)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you do it graphing? That would be a great help to have both methods.
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