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anonymous

  • 5 years ago

The altitude of a triangle is increasing at a rate of 2 centimeters/minute while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters?

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  1. bahrom7893
    • 5 years ago
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    i really think you should practice related rates, working on your other problem right now

  2. anonymous
    • 5 years ago
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    hey

  3. bahrom7893
    • 5 years ago
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    hey will do this one later, i gotta eat

  4. anonymous
    • 5 years ago
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    carra?

  5. anonymous
    • 5 years ago
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    yes

  6. anonymous
    • 5 years ago
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    want me to solve it

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    Area of triangle = 1/2 base * altitude

  9. anonymous
    • 5 years ago
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    area is changing with respect to time, base is changing with respect to time and altitude is changing with respect to time . so taking derivative we have

  10. anonymous
    • 5 years ago
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    product rule , which is complicated... ok lets look for a relationship given

  11. anonymous
    • 5 years ago
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    ok product rule it is

  12. anonymous
    • 5 years ago
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    dA/dt = 1/2 b * da/dt + 1/2 db/dt * a , where a is altitude

  13. anonymous
    • 5 years ago
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    b is base, A is area

  14. anonymous
    • 5 years ago
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    da/dt = 2 "The altitude of a triangle is increasing at a rate of 2 centimeters/minute " dA/dt = 3.5 "while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute." At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters? what is db/dt , when a = 10 , and A= 95

  15. anonymous
    • 5 years ago
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    dA/dt = 1/2 b * da/dt + 1/2 db/dt * a we have to go back and solve for b here to find db/dt

  16. anonymous
    • 5 years ago
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    A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

  17. anonymous
    • 5 years ago
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    A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

  18. anonymous
    • 5 years ago
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    plug back into dA/dt = 1/2 b * da/dt + 1/2 db/dt * a 3.5 = 1/2 * 19 *2 + 1/2 * db/dt * 10 , and solve for db/dt

  19. bahrom7893
    • 5 years ago
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    http://i52.tinypic.com/263ww2c.jpg

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