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anonymous
 5 years ago
The altitude of a triangle is increasing at a rate of 2 centimeters/minute while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters?
anonymous
 5 years ago
The altitude of a triangle is increasing at a rate of 2 centimeters/minute while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters?

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0i really think you should practice related rates, working on your other problem right now

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0hey will do this one later, i gotta eat

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Area of triangle = 1/2 base * altitude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0area is changing with respect to time, base is changing with respect to time and altitude is changing with respect to time . so taking derivative we have

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0product rule , which is complicated... ok lets look for a relationship given

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok product rule it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dA/dt = 1/2 b * da/dt + 1/2 db/dt * a , where a is altitude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0da/dt = 2 "The altitude of a triangle is increasing at a rate of 2 centimeters/minute " dA/dt = 3.5 "while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute." At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters? what is db/dt , when a = 10 , and A= 95

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dA/dt = 1/2 b * da/dt + 1/2 db/dt * a we have to go back and solve for b here to find db/dt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plug back into dA/dt = 1/2 b * da/dt + 1/2 db/dt * a 3.5 = 1/2 * 19 *2 + 1/2 * db/dt * 10 , and solve for db/dt
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