anonymous
  • anonymous
need an explanation: suppose 2J of work is needed to stretch spring w/ natural length of 30 cm to 42 cm. how much work is needed to stretch spring from 35cm to 40 cm? how far beyond natural length will force of 30 N keep spring stretched?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
work done on spring = 0.5 kx^2 = 2J, where k is the spring constant and x is the extension from rest thus find the spring constant of the spring...as it implies it is a constant: thus 2 = 0.5 kx^2 = 0.5 *k*0.12^2 (extension from rest = (42 -30)cm = 12cm =0.12m so 1 = k*0.12^2 and k = 1/0.12^2 = 69.4 N/m Now you can find the work for an extension of 35cm to 40 cm(0.35m to 0.40 m) work = 0.5 69.4(0.05)^2 = 0.08675 J of work how far beyond natural length for a force of 30 N: Now F=kx, k = 69.4, therefore x = F/k = 30/69.4 = 0.432m = 43.2cm

Looking for something else?

Not the answer you are looking for? Search for more explanations.