anonymous
  • anonymous
40 students live in a dormitory. 5 have swine flu. If 4 students are selected at random, what is the probability that 1 or 2 of the 4 have swine flu?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
(5/40)(4/39)((3/37)= 1.03950104*10^-3
anonymous
  • anonymous
This is not the correct answer
anonymous
  • anonymous
can u tell me what it is please, i suck at probablity, my weakest subject

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anonymous
  • anonymous
Google'd and discovered this.... http://www.jiskha.com/display.cgi?id=1298256153
anonymous
  • anonymous
no problem. so I found (40 nCr 4)= 91390 then \[(35 nCr 3)(5 nCr 1)+(35 nCr 2)(5 nCr 2)=38675\] then \[38675\div91390=0.423\]
anonymous
  • anonymous
I actually posted that crsf29 and they didnt have the right answer either
anonymous
  • anonymous
Did it work out for you? I could dig out my ProbStat book and help you, but it would take me about 20 minutes and I'd wake my roomies...Sorry.
anonymous
  • anonymous
you dont have to do that I figured it out

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