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  • 5 years ago

A particle is moving along the curve y=3 sqrt 2x+5 . As the particle passes through the point (2,9), its -coordinate increases at a rate of 4 units per second. Find the rate of change of the distance from the particle to the origin at this instant

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  1. anonymous
    • 5 years ago
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    Differentiating the equation wrt time dy/dt=3dx/dt (2x+5)^(-1/2) As dy/dt=4, we can put x=2 for the given point and find that dx/dt=4. distance from origin R= sqrt (x^2 + y^2) We have to find dR/dt = [xdx/dt + ydy/dt]/[sqrt D] Knowing x,y, dx/dt and dy/dt at that point we can evaluate the answer

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