Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Improper integrals: how do i know when the limit is coming from the left or the right?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

You decide how to approach the limit, and denote it as such....Lim as x->0+ or lim as x->0- Would be read as Limit as x approaches 0 from the right, etc.... You can replace the limit as x approaches 0 with x approaching any number...
ex. \[\lim_{L \rightarrow 7} \int\limits_{7}^{0}\]
proper coded notation is as follows.....using 9/x as the limit to be evaluated approached from the left.... lim_(x->9^-) 9/x = 1

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[\lim_{L \rightarrow 7}\int\limits_{L}^{7}1/{(x-7)^{2}}\]
Yes, imignott is correct
How do i know when L is going to 7 from the left or the right?
because the limit is on the lower bound, would mean approached from the left, or lower end of the number line.... Vice versa for upper bound and from the right...

Not the answer you are looking for?

Search for more explanations.

Ask your own question