anonymous
  • anonymous
Improper integrals: how do i know when the limit is coming from the left or the right?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
You decide how to approach the limit, and denote it as such....Lim as x->0+ or lim as x->0- Would be read as Limit as x approaches 0 from the right, etc.... You can replace the limit as x approaches 0 with x approaching any number...
anonymous
  • anonymous
ex. \[\lim_{L \rightarrow 7} \int\limits_{7}^{0}\]
anonymous
  • anonymous
proper coded notation is as follows.....using 9/x as the limit to be evaluated approached from the left.... lim_(x->9^-) 9/x = 1

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[\lim_{L \rightarrow 7}\int\limits_{L}^{7}1/{(x-7)^{2}}\]
anonymous
  • anonymous
Yes, imignott is correct
anonymous
  • anonymous
How do i know when L is going to 7 from the left or the right?
anonymous
  • anonymous
because the limit is on the lower bound, would mean approached from the left, or lower end of the number line.... Vice versa for upper bound and from the right...

Looking for something else?

Not the answer you are looking for? Search for more explanations.