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i'm gonna go with 16.67%^3=0.00463241...

So, as a percentage, 0.463%

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GODinme it is the sum of 7 or 11

ok...that wasn't in the question...who's asking the question?

7 or 11? Thats a Craps problem...Google will help...

heartslayer20 asked it..........

so how do you know what it's sposed to be?

probability that 7or 11 appear at at least 2 times
= 3C2 * (2/9)^2 * (7/9) + 3C3 *(2/9)^3

probability of a 7, 1/6th probability of an 11, 1/18th. Multiply ad nauseum...

ok....

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