anonymous
  • anonymous
How can I consolidate a Tuple e.g. make (1,5,4,6,5,2,5,1) just (1,2,4,5,6)
MIT 6.00 Intro Computer Science (OCW)
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The simple way to do it is to make a new empty tuple variable. Then have 2 nested for loops that iterate over the unconsolidated tuple, and the new tuple. If the current item in the unconsolidated tuple exists in the consolidated tuple, change the value of a state variable. Once the iterating over the new tuple is done, check the value of the state variable and add the value to the new tuple accordingly.
anonymous
  • anonymous
ok sounds good I'll try that, is there anyway to order the integers by value?
anonymous
  • anonymous
Umm, I think it would be easiest to use some sorting algorithm on the tuple once you've got it filtered to unique values. Wikipedia has a bunch of sorting algorithm articles you can reference. Although, thinking about it more, it might be easier to first sort the values, then you can just iterate through it, checking to see if the value in the adjacent index is the same.

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anonymous
  • anonymous
tuples are immutable, so you can't just sort them. You would have to create a new tuple, with the items already sorted...or so the documentation indicates.
anonymous
  • anonymous
ok finally figured this out a=(5,2,2,1,4,4,1,6,34,34,34,34,34,34,65,5,32,1,12,34,63,34,34,7,5,6) b=() c=() e=() d=0 f=0 for n in range(0,len(a)): value = a[n] d=0 f=0 for m in range(0,len(a)): for j in range(0,len(a)): for k in range(0,len(b)): if b[k]==value: f+=1 if f==1: break if a[j] >= value: d+=1 if d==len(a)-m: b+=(value,) d=0 f=0 t=(len(b)) while t>0: for m in range(0,len(b)): value = b[m] for y in range(0,len(b)): if b[y] >= value: d+=1 if d==len(b): c+=(value,) f+=1 if f<1: e+=(value,) d=0 f=0 b=e e=() t-=1 works if you had the same question, although it probably could be a lot simpler
anonymous
  • anonymous
and c is the final answer
anonymous
  • anonymous
Here's something a little shorter...same idea I think. :-) def duplicates(): a = (1,1,1,2,2,2,3,3,3,4,4,4) b = [] c = () for i in a: if i not in b: b.append(i) for i in b: if i not in c: c = c + (i,) a = c print a
anonymous
  • anonymous
oh - ps. You don't need the "if i not in c:" The list b is already sorted with the unique items, and you nly need to make a tuple from the list. So it should read: def duplicates(): a = (1,1,1,2,2,2,3,3,3,4,4,4) print "Original Tuple:", a b = [] c = () for i in a: if i not in b: b.append(i) for i in b: c = c + (i,) a = c print "And the survey says!", a
anonymous
  • anonymous
If you want, you can also add: b.sort() after the b.append(i)
anonymous
  • anonymous
The best solution is to use the builtin set datatype. It's an unsorted collection of unique elements. a = (1,1,1,2,3,4,2,3,1,4,5) a = tuple(sorted(set(a)))
anonymous
  • anonymous
Yes - SORTED will work nicely. I wasn't at that point yet, but nopw I intend to read and study a little further...there is so much to learn.
anonymous
  • anonymous
Just ignore that last post, this webpage put it on the wrong thread.
anonymous
  • anonymous
Nevermind, I was seeing a post here that I made in a different thread. Argh.

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