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lgg23
 5 years ago
Solve for x in terms of k.
log base 5 of x  log base 5 of (x+10) = log base 5 of k
lgg23
 5 years ago
Solve for x in terms of k. log base 5 of x  log base 5 of (x+10) = log base 5 of k

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0log5(x)log5(x+10) = log5(k) log5(x/x+10) = log5(k) x/(x+10) = k x=k(x+10) x=kx+10k x(1k)=10k x=10k/(1k)

lgg23
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get the second to last step? where its x(1k)=10k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=kx+10k group like terms i.e. terms with x xkx=10k x(1k)=10k x=10k/(1k)

lgg23
 5 years ago
Best ResponseYou've already chosen the best response.0you went through the problem faster then i could process it in my head. thank you.
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