## anonymous 5 years ago translate and solve. the product of seven and the difference between a number times negative two and two is negative forty two

1. anonymous

We have product of 7, and "difference between a number times two, and two" equals -42. Rewrite this as an equation, and let a be the unknown number: $7 \times [(a \times -2) - 2] = -42$ divide by 7 on both sides: $(a \times -2) - 2 = -6]\ add 2 two both sides: \[a \times -2 = -4]\ finally divide by -2 on both times to isolate a \[a = 2]\ 2. anonymous We have product of 7, and "difference between a number times two, and two" equals -42. Rewrite this as an equation, and let a be the unknown number: \[7 \times [(a \times -2) - 2] = -42$ divide by 7 on both sides: $(a \times -2) - 2 = -42$ add 2 to both sides:

3. anonymous

(continued) $a \times -2 = -4$ finally, divide by -2 on both sides to get a: $a = 2$

4. anonymous

what is the integral of x sin x dx