## anonymous 5 years ago find the indicated derivatives f(x)=1/2x+3, y''

1. anonymous

Just to be sure, is this f(x) = (1/2)x + 3, or f(x) = 1/(2x +3)?

2. anonymous

its f(x)=1/(2x+3)

3. anonymous

well then, we have $f'(x) = (-1/(2x + 3)^2)\times 2 = -2/(2x+3)^2$ where the multiplication by 2 occurs by the chain rule and then $f''(x) = (4/(2x+3)^3)\times 2 = 8/(2x+3)^3$

4. anonymous

ohh okay! thanks so much!