A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
its says solve the equation allgebraically. Check for extraneous solutions. The equation is: 4x/x+4 + 3/x1 = 15/x^2+3x4. can anyone help?
anonymous
 5 years ago
its says solve the equation allgebraically. Check for extraneous solutions. The equation is: 4x/x+4 + 3/x1 = 15/x^2+3x4. can anyone help?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you put parenthesis under the correct denominators?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04x/(x+4) + 3/(x1) = 15/(x^2+3x4), is that what you mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes it is. So the first thing to realize is that on the right side, under the 15, is a factorable quadratic equation, so rewrite like: \[4x/(x + 4) + 3/(x 1) = 15/((x + 4)(x 1))\] We are going to multiply by (x + 4)(x  1) on both sides, and note where they cancel appropriately: \[4x(x1) + 3(x + 4) = 15\] multiply everything out, collect like terms, and move everything over to one side so we can then either factor of use the quadratic equation: \[4x^2  4x + 3x + 12 = 15 \rightarrow 4x^2  x  3 = 0\] no need for the quadratic equation, this factors into: (4x + 3)(x  1) = 0 setting each term equals to 0 yields x = 3/4 and x = 1. Be sure to plug back into your original equaiton to see that this works

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much pyeh9, that was a really big help. :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.