A community for students.
Here's the question you clicked on:
 0 viewing
bahrom7893
 5 years ago
Differential equations help!
y*dx + (3+3xy)*dy = 0
The topic is integrating factors
The answer is 4xy^3 + 4y^3  y^4 = C
bahrom7893
 5 years ago
Differential equations help! y*dx + (3+3xy)*dy = 0 The topic is integrating factors The answer is 4xy^3 + 4y^3  y^4 = C

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0want me to use that list thingy

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2just a solution, its integrating factors, its just my brains are dead

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean by integrating factors?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2you know when you let something be [e^Integral(f(x;y))dx] then multiply across by it to get a derivative of some expression on the right and some ez integral on the left or vice versa

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you have y + dy/dx ( 3 + 3x y) = 0

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2well yeah then move y over

sasogeek
 5 years ago
Best ResponseYou've already chosen the best response.0does it mean you're basically trying to prove the answer?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2no I just know the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well for integrating factors we want dy/dx + p(x)y = g(x)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2oh okay then i can solve it i think

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2integrating factor is e^x, lemme try this will let u guys know how it goes

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2wait no its not, but at least now i know the expression, tryin to solve afk

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here, this is called exact equation http://tutorial.math.lamar.edu/Classes/DE/Exact.aspx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0M(x,y) + N(x,y)dy/dx = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont kill yourself bahrom this website is buggy, everytime i type something it freezes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have you done partial derivatives?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.2i have, but as i said my brains are not functionin at all, just too tired

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we are looking for a function Fx (x,y) + Fy (x,y) dy/dx = 0, where Fx is the partial derivative of F(x,y) with respect to x (treat y as a constant) and Fy is the partial derivative of F(x,y) with respect to y (treat x as a constant)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We have the equation M(x,y) dx + N(x,y) dy = 0 or M (x,y) + N(x,y)dy/dx = 0 M(x,y) = y and N(x,y) = 3 + 3x  y remember we can solve this and its called "exact" if M(x,y) = Fx (x,y) and N(x,y) = Fy (x,y), where Fx is the partial derivative of F(x,y) with respect to x (treat y as a constant) and Fy is the partial derivative of F(x,y) with respect to y (treat x as a constant) so if we have Fx (x,Y) + Fy (x,y) dy/dx = 0, then F(x,y) is our solution . ok so the last thing , assuming there exists such a F(x,y) it must be the case that Fxy = Fyx which is true for all continuous F(x,y). By substituting Fx = M and Fy = N we have My = Nx . So here Mx = 0 , and Ny = 1 . hmmm, not exact ok now we move to plan B and introduce an integrating factor http://www.cliffsnotes.com/study_guide/IntegratingFactors.topicArticleId19736,articleId19711.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here is another website http://www.sosmath.com/diffeq/first/exact/exact.html and they have a non exact first order ode
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.