a 44-foot of wire is cut into three pieces so that the second piece is four times the length of the first piece, and the third piece is six feet less than five times the length of the first piece. find the length of the pieces

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a 44-foot of wire is cut into three pieces so that the second piece is four times the length of the first piece, and the third piece is six feet less than five times the length of the first piece. find the length of the pieces

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Notice how the problem keeps referencing all the lengths in terms of "the first piece". It's usually a good idea to say "ok, let the length of first piece = X." First piece = X Second piece = "four times the length of ... X" Third piece = "Six feet less than five times the length of ... X" Now, the WHOLE wire is 44 ft long. So add up those three parts and set it equal to 44. You will have an equation with X + constant = 44. From there, it's a bit of algeba, and that'll give you the answer for X, which we must remember is the length of THE FIRST PIECE. You still have to take "X" and figure out what the other pieces are. (multiply by four... multiply by 5 and add six feet.) Hope this helps!

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