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anonymous

  • 5 years ago

i cant seem to find the derivitave of the square root(3x+1). Any idea how to help?

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  1. anonymous
    • 5 years ago
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    d/dx (3x+1)^(1/2) = (1/2)(3x+1)^(-1/2) (3) = (3/2)(3x+1)^(-1/2)

  2. anonymous
    • 5 years ago
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    \[\frac{3}{2 \sqrt{3 x+1}}\] Just use the chain rule. The inside or u would be 3x+1

  3. anonymous
    • 5 years ago
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    SUPER THANKS!! We havent been taught this chain rule tho i have seen it talked about on google. I came up with 3/3x+1

  4. anonymous
    • 5 years ago
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    um... d/dx(3x+1)^(1/2) to change the square root into a power. for the power rule...

  5. anonymous
    • 5 years ago
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    the answer is (1/2)*(3x+1)^(1/2)*(3), you can learn more about the power rule here: http://en.wikipedia.org/wiki/Calculus_with_polynomials#Power_rule

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