An open rectangular box has square base and a fixed outer surface area of 108cm^2.
Show that x^2+4xy=108.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Imagine a box standing up with the square base on the bottom. Let the square base have side length x and let the height of the box be y.
Then the total outer surface area is the sum of the areas of the outer faces.
Normally we have six faces for a rectangular box. But here it says we have an open rectangular box, so the top square face has been removed.
So now we only have the bottom square base and the four remaining rectangular faces.
The area of each rectangular face is xy.
And the area of the square base is x^2.
So we have x^2 + 4xy = 108.
You could solve for Y and get
Y= (-x^2 + 108)/ 4x
Then you could plug that into your equation and solve for X and then plug in your value for X to solve for Y. Once you have both of your values for X and Y you could plug them in to your equation to verify that your arguments are correct. So basically you make sure that for example 5=5, at the end. So you make sure that a number does equal the number that it is the same number. By that happening we have proved that the equation is correct.