## anonymous 5 years ago Determine the convergence or divergence of the series. (2n)!/[(n-1)3^n]

1. anonymous

Diverge, because n! has a higher order than b^n for any constant b.

2. mathteacher1729

Do you mean $\frac{n!}{(n-1)3^n}$ or $\frac{n!}{(n-1)^{3n}}$ ?

3. mathteacher1729

Either of those is sequence, not a series. A sequence effectively a list of numbers. A series tells you to "add up all the numbers in the sequence."

4. anonymous

Regardless of whether they're sequences or series, the nth terms don't converge anyway. I didn't notice the second interpretation. Hmm...