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anonymous
 5 years ago
dy/dx of cos(x+y)=x.
anonymous
 5 years ago
dy/dx of cos(x+y)=x.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I came up with  (1+sin(x+y))/(sin(x+y)) but it doesn't really seem right? If you can help, please do. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cos(x+y)=x\] \[\cos^{1} x=x+y\] \[y=\cos^{1} xx\] \[dy/dx=(\cos^{1} xx)\prime\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[dy/dx=1/\sqrt{1x^2}1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i hope i am not doing any mistake...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if this is right, fan me plz.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You probably used implicit differentiation heist. If you did, then you'd get your answer (and I got the same thing). You could also check it here. http://www.wolframalpha.com/input/?i=derivative+of+cos%28x+%2B+y+%29+%3D+x eDadou, I'm not sure why your method doesn't give the same answer. I think it might have to do with taking the arccosine of both sides, since that then restricts the domain over which x can vary.
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