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dy/dx of cos(x+y)=x.

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I came up with - (1+sin(x+y))/(sin(x+y)) but it doesn't really seem right? If you can help, please do. :)
\[\cos(x+y)=x\] \[\cos^{-1} x=x+y\] \[y=\cos^{-1} x-x\] \[dy/dx=(\cos^{-1} x-x)\prime\]

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i hope i am not doing any mistake...
if this is right, fan me plz.
You probably used implicit differentiation heist. If you did, then you'd get your answer (and I got the same thing). You could also check it here. eDadou, I'm not sure why your method doesn't give the same answer. I think it might have to do with taking the arccosine of both sides, since that then restricts the domain over which x can vary.
yeah probably.

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