## anonymous 5 years ago The derivative of 3/t^3/5 - 6/t^1/2

1. mathteacher1729

Do you mean $\frac{dy}{dx}(\frac{3}{t^{3/5}}-\frac{6}{t^{1/2}})$ ?

2. anonymous

Yes

3. mathteacher1729

Ok, you must use two rules here: $1/x^n = x^{-n}$ and $\frac{dy}{dx}x^k = kx^{k-1}$ So re-write this as $\frac{dy}{dx}(3t^{-3/5}-6t^{-1/2})$

4. anonymous

Thanks!

5. mathteacher1729

You do know that what I wrote is not the final answer, right? You still have to differentiate according to those rules. :)