logarithms anyone?

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- anonymous

logarithms anyone?

- schrodinger

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- bahrom7893

i gotta revise those too, so what are the questions?

- anonymous

how do i get the inverse y=logsub3x

- anonymous

so its y=(little3at the bottom)x

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## More answers

- bahrom7893

k

- bahrom7893

\[y=\log_{3}x \]
\[3^{y}=x\]
So x = y^3 is that what u mean by inverse?

- anonymous

the inverse of the function

- anonymous

i dont get that either

- bahrom7893

http://www.andrews.edu/~calkins/math/webtexts/numb17.htm
sorry havent done logs in a long time, i only use Ln,s but that is the inverse function

- bahrom7893

inverse function is:
Say:
y = f(x)
then inverse is: x = F^-1 (y), which basically means solve for X

- anonymous

ok thank you soo much

- bahrom7893

hey can u check the answer key.. like gimme any problem with an answer to it

- bahrom7893

and ill make sure the answer's right

- anonymous

answer key? like in the back of the book?

- anonymous

ummm, this is a unit 4 test that was left for hw, so we cant look at the answers in the back of the book T_T

- bahrom7893

just gimme any similar problems from the book that has an answer to it

- bahrom7893

like anything like y = log(sub5)x and then it has an answer.. numbers dont matter

- anonymous

ok, wait a sec

- anonymous

13. y=logsubX

- anonymous

answer: f^-19x0=7^x

- anonymous

*answer: f^-1(x)=7^x

- bahrom7893

u forgot to add what is under sub

- anonymous

sorry the second is the real answer

- anonymous

there is no under sub

- bahrom7893

Oh its just \[y = \log_{} x\]

- bahrom7893

?

- anonymous

ya, its: y=log(undersub7) X

- anonymous

answer:f^-1(x)=7^x

- bahrom7893

Okay that makes sense now

- anonymous

sorry if i confused you!

- bahrom7893

So my answer wasn't technically wrong but still it was in wrong notation

- bahrom7893

workin on the first one

- anonymous

oh alright

- bahrom7893

\[y=\log_{3}x ; x = 3^{y} ; f ^{-1} (x) = 3^{x}\]

- anonymous

i understood everything till the last setp

- bahrom7893

oh for you to make it into inverse, just replace y with x, say:
Sin(x) = y; Sin^-1(y) = x

- anonymous

so would i have to put it as :
\[\prime-1(x)=3^{x}\]

- anonymous

i meant f^-1(x)=3^x

- bahrom7893

yes

- anonymous

hmm, i was pretty sure you could have answered it differently. it cant be:
y=3^x

- bahrom7893

http://www.sosmath.com/algebra/logs/log4/log45/log4513/log4513.html

- anonymous

oh thanks that seems helpful, can i ask 1 more and see if i get it?

- bahrom7893

yeah

- anonymous

f(x)=lnx

- anonymous

ok, i dont even know what to do here,

- anonymous

we basically solve for x, right?

- bahrom7893

yup and this is my favourite stuff!
so useful in calculus

- bahrom7893

k so Lnx is the same as Log(sub e)X, where e is approximately 2.71

- anonymous

right

- anonymous

oh,. sorry, how can i add you as a fan?

- anonymous

oh, nvm, haha

- bahrom7893

sure lol

- anonymous

ok, so i get it so far

- bahrom7893

good and start a new topic. this is getting annoying, my browser keeps scrollin up and down. this place is buggy

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