logarithms anyone?

- anonymous

logarithms anyone?

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- bahrom7893

i gotta revise those too, so what are the questions?

- anonymous

how do i get the inverse y=logsub3x

- anonymous

so its y=(little3at the bottom)x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- bahrom7893

k

- bahrom7893

\[y=\log_{3}x \]
\[3^{y}=x\]
So x = y^3 is that what u mean by inverse?

- anonymous

the inverse of the function

- anonymous

i dont get that either

- bahrom7893

http://www.andrews.edu/~calkins/math/webtexts/numb17.htm
sorry havent done logs in a long time, i only use Ln,s but that is the inverse function

- bahrom7893

inverse function is:
Say:
y = f(x)
then inverse is: x = F^-1 (y), which basically means solve for X

- anonymous

ok thank you soo much

- bahrom7893

hey can u check the answer key.. like gimme any problem with an answer to it

- bahrom7893

and ill make sure the answer's right

- anonymous

answer key? like in the back of the book?

- anonymous

ummm, this is a unit 4 test that was left for hw, so we cant look at the answers in the back of the book T_T

- bahrom7893

just gimme any similar problems from the book that has an answer to it

- bahrom7893

like anything like y = log(sub5)x and then it has an answer.. numbers dont matter

- anonymous

ok, wait a sec

- anonymous

13. y=logsubX

- anonymous

answer: f^-19x0=7^x

- anonymous

*answer: f^-1(x)=7^x

- bahrom7893

u forgot to add what is under sub

- anonymous

sorry the second is the real answer

- anonymous

there is no under sub

- bahrom7893

Oh its just \[y = \log_{} x\]

- bahrom7893

?

- anonymous

ya, its: y=log(undersub7) X

- anonymous

answer:f^-1(x)=7^x

- bahrom7893

Okay that makes sense now

- anonymous

sorry if i confused you!

- bahrom7893

So my answer wasn't technically wrong but still it was in wrong notation

- bahrom7893

workin on the first one

- anonymous

oh alright

- bahrom7893

\[y=\log_{3}x ; x = 3^{y} ; f ^{-1} (x) = 3^{x}\]

- anonymous

i understood everything till the last setp

- bahrom7893

oh for you to make it into inverse, just replace y with x, say:
Sin(x) = y; Sin^-1(y) = x

- anonymous

so would i have to put it as :
\[\prime-1(x)=3^{x}\]

- anonymous

i meant f^-1(x)=3^x

- bahrom7893

yes

- anonymous

hmm, i was pretty sure you could have answered it differently. it cant be:
y=3^x

- bahrom7893

http://www.sosmath.com/algebra/logs/log4/log45/log4513/log4513.html

- anonymous

oh thanks that seems helpful, can i ask 1 more and see if i get it?

- bahrom7893

yeah

- anonymous

f(x)=lnx

- anonymous

ok, i dont even know what to do here,

- anonymous

we basically solve for x, right?

- bahrom7893

yup and this is my favourite stuff!
so useful in calculus

- bahrom7893

k so Lnx is the same as Log(sub e)X, where e is approximately 2.71

- anonymous

right

- anonymous

oh,. sorry, how can i add you as a fan?

- anonymous

oh, nvm, haha

- bahrom7893

sure lol

- anonymous

ok, so i get it so far

- bahrom7893

good and start a new topic. this is getting annoying, my browser keeps scrollin up and down. this place is buggy

Looking for something else?

Not the answer you are looking for? Search for more explanations.