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anonymous
 5 years ago
logarithms anyone?
anonymous
 5 years ago
logarithms anyone?

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta revise those too, so what are the questions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i get the inverse y=logsub3x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so its y=(little3at the bottom)x

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\log_{3}x \] \[3^{y}=x\] So x = y^3 is that what u mean by inverse?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the inverse of the function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont get that either

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.andrews.edu/~calkins/math/webtexts/numb17.htm sorry havent done logs in a long time, i only use Ln,s but that is the inverse function

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0inverse function is: Say: y = f(x) then inverse is: x = F^1 (y), which basically means solve for X

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank you soo much

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0hey can u check the answer key.. like gimme any problem with an answer to it

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0and ill make sure the answer's right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0answer key? like in the back of the book?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ummm, this is a unit 4 test that was left for hw, so we cant look at the answers in the back of the book T_T

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0just gimme any similar problems from the book that has an answer to it

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0like anything like y = log(sub5)x and then it has an answer.. numbers dont matter

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0u forgot to add what is under sub

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the second is the real answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no under sub

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Oh its just \[y = \log_{} x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya, its: y=log(undersub7) X

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Okay that makes sense now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry if i confused you!

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0So my answer wasn't technically wrong but still it was in wrong notation

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0workin on the first one

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\log_{3}x ; x = 3^{y} ; f ^{1} (x) = 3^{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understood everything till the last setp

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0oh for you to make it into inverse, just replace y with x, say: Sin(x) = y; Sin^1(y) = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would i have to put it as : \[\prime1(x)=3^{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, i was pretty sure you could have answered it differently. it cant be: y=3^x

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.sosmath.com/algebra/logs/log4/log45/log4513/log4513.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh thanks that seems helpful, can i ask 1 more and see if i get it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, i dont even know what to do here,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we basically solve for x, right?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0yup and this is my favourite stuff! so useful in calculus

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0k so Lnx is the same as Log(sub e)X, where e is approximately 2.71

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh,. sorry, how can i add you as a fan?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so i get it so far

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0good and start a new topic. this is getting annoying, my browser keeps scrollin up and down. this place is buggy
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