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anonymous

  • 5 years ago

Question: you want to mix two brands of juice together to produce 120 gallons of a 3/5 cranberry juice blend. Brand A contains 11/20 cranberry juice and Brand B contains 7/10 cranberry juice. How much of each brand should you mix together?

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  1. bahrom7893
    • 5 years ago
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    will try to get to this, helpin someone at the moment

  2. anonymous
    • 5 years ago
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    please tryy!

  3. bahrom7893
    • 5 years ago
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    btw do u have the answer to it?

  4. bahrom7893
    • 5 years ago
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    bcuz it would make life so much easier

  5. anonymous
    • 5 years ago
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    i think its 80 for a and 40 for b

  6. bahrom7893
    • 5 years ago
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    k tnx

  7. anonymous
    • 5 years ago
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    yupp

  8. anonymous
    • 5 years ago
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    SO what you do is try and figure out how much each Brand contains in cranberry juice in a fraction where 120 gal is the denominator. So A has 66/20 B has 84/120 You make an equation then A(66/230)+ B(84/120)= 72/120 72/120 is 3/5 A and B in the equation are our variables, or the things we can change or that can change.

  9. anonymous
    • 5 years ago
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    You then use substitution \[A=(-B(84/120)+72/120)/66/120\]

  10. anonymous
    • 5 years ago
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    Sorry the value next to A in the equation is 66/120 not 66/230. I Dnt Know what I was thinking.

  11. anonymous
    • 5 years ago
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    its finee!

  12. anonymous
    • 5 years ago
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    So you simplify what A equals A=(-B(84/120)+72/120)/66/120 since you are dividing by fractions it is the same as saying A=(-B(84/120)+72/120) times 120/66

  13. anonymous
    • 5 years ago
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    why is b negative

  14. anonymous
    • 5 years ago
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    So what you do is substitute what you found A to be in terms of B into the equation. You then only have B as a variable in the equation. Solve for B. Now you still d0on't know what A is exactly in numbers. Plug in the exact value for B.

  15. anonymous
    • 5 years ago
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    wait was my answer correct? im honestly so confused

  16. anonymous
    • 5 years ago
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    You plug B into one of the equations you have that involve the variable A. You probably want to use the one that has A equals something, because you already have A isolated.

  17. anonymous
    • 5 years ago
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    A=-B(84/66) + (72/66) The 120s cancel

  18. anonymous
    • 5 years ago
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    Then you could plug what A equals into the equation A(66/120) + B(84/120)=72/120 you get (-B(84/66)+ (72/66)) (66/120) + B(84/120)=72/120

  19. anonymous
    • 5 years ago
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    You distribute the 66/120 and get (-B(84/120)+(72/120)+B(84/120)=72/120

  20. anonymous
    • 5 years ago
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    Ummmmnh I just realized that I must be solving it wrong. Because the equation that I last gave you comes out to 0=0, which is true, but not what we need.

  21. anonymous
    • 5 years ago
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    Sorry

  22. anonymous
    • 5 years ago
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    itss okayy!

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