anonymous
  • anonymous
Question: you want to mix two brands of juice together to produce 120 gallons of a 3/5 cranberry juice blend. Brand A contains 11/20 cranberry juice and Brand B contains 7/10 cranberry juice. How much of each brand should you mix together?
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

bahrom7893
  • bahrom7893
will try to get to this, helpin someone at the moment
anonymous
  • anonymous
please tryy!
bahrom7893
  • bahrom7893
btw do u have the answer to it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

bahrom7893
  • bahrom7893
bcuz it would make life so much easier
anonymous
  • anonymous
i think its 80 for a and 40 for b
bahrom7893
  • bahrom7893
k tnx
anonymous
  • anonymous
yupp
anonymous
  • anonymous
SO what you do is try and figure out how much each Brand contains in cranberry juice in a fraction where 120 gal is the denominator. So A has 66/20 B has 84/120 You make an equation then A(66/230)+ B(84/120)= 72/120 72/120 is 3/5 A and B in the equation are our variables, or the things we can change or that can change.
anonymous
  • anonymous
You then use substitution \[A=(-B(84/120)+72/120)/66/120\]
anonymous
  • anonymous
Sorry the value next to A in the equation is 66/120 not 66/230. I Dnt Know what I was thinking.
anonymous
  • anonymous
its finee!
anonymous
  • anonymous
So you simplify what A equals A=(-B(84/120)+72/120)/66/120 since you are dividing by fractions it is the same as saying A=(-B(84/120)+72/120) times 120/66
anonymous
  • anonymous
why is b negative
anonymous
  • anonymous
So what you do is substitute what you found A to be in terms of B into the equation. You then only have B as a variable in the equation. Solve for B. Now you still d0on't know what A is exactly in numbers. Plug in the exact value for B.
anonymous
  • anonymous
wait was my answer correct? im honestly so confused
anonymous
  • anonymous
You plug B into one of the equations you have that involve the variable A. You probably want to use the one that has A equals something, because you already have A isolated.
anonymous
  • anonymous
A=-B(84/66) + (72/66) The 120s cancel
anonymous
  • anonymous
Then you could plug what A equals into the equation A(66/120) + B(84/120)=72/120 you get (-B(84/66)+ (72/66)) (66/120) + B(84/120)=72/120
anonymous
  • anonymous
You distribute the 66/120 and get (-B(84/120)+(72/120)+B(84/120)=72/120
anonymous
  • anonymous
Ummmmnh I just realized that I must be solving it wrong. Because the equation that I last gave you comes out to 0=0, which is true, but not what we need.
anonymous
  • anonymous
Sorry
anonymous
  • anonymous
itss okayy!

Looking for something else?

Not the answer you are looking for? Search for more explanations.