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Question: you want to mix two brands of juice together to produce 120 gallons of a 3/5 cranberry juice blend. Brand A contains 11/20 cranberry juice and Brand B contains 7/10 cranberry juice. How much of each brand should you mix together?

Mathematics
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will try to get to this, helpin someone at the moment
please tryy!
btw do u have the answer to it?

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Other answers:

bcuz it would make life so much easier
i think its 80 for a and 40 for b
k tnx
yupp
SO what you do is try and figure out how much each Brand contains in cranberry juice in a fraction where 120 gal is the denominator. So A has 66/20 B has 84/120 You make an equation then A(66/230)+ B(84/120)= 72/120 72/120 is 3/5 A and B in the equation are our variables, or the things we can change or that can change.
You then use substitution \[A=(-B(84/120)+72/120)/66/120\]
Sorry the value next to A in the equation is 66/120 not 66/230. I Dnt Know what I was thinking.
its finee!
So you simplify what A equals A=(-B(84/120)+72/120)/66/120 since you are dividing by fractions it is the same as saying A=(-B(84/120)+72/120) times 120/66
why is b negative
So what you do is substitute what you found A to be in terms of B into the equation. You then only have B as a variable in the equation. Solve for B. Now you still d0on't know what A is exactly in numbers. Plug in the exact value for B.
wait was my answer correct? im honestly so confused
You plug B into one of the equations you have that involve the variable A. You probably want to use the one that has A equals something, because you already have A isolated.
A=-B(84/66) + (72/66) The 120s cancel
Then you could plug what A equals into the equation A(66/120) + B(84/120)=72/120 you get (-B(84/66)+ (72/66)) (66/120) + B(84/120)=72/120
You distribute the 66/120 and get (-B(84/120)+(72/120)+B(84/120)=72/120
Ummmmnh I just realized that I must be solving it wrong. Because the equation that I last gave you comes out to 0=0, which is true, but not what we need.
Sorry
itss okayy!

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