anonymous
  • anonymous
[\sqrt{d ^{2}-19} -2d + 11=0
Mathematics
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SOLVED
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chestercat
  • chestercat
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bahrom7893
  • bahrom7893
wait can u repost the question?
bahrom7893
  • bahrom7893
is it the same that i answered?
anonymous
  • anonymous
no i typed it wrong the first time

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bahrom7893
  • bahrom7893
So can u repost it, i still dont see the right question
anonymous
  • anonymous
\[\sqrt{d ^{2}-19}-2d+11=0\]
bahrom7893
  • bahrom7893
okay
bahrom7893
  • bahrom7893
\[\sqrt{d^2 - 19} = 2d - 11\] Move -2d and 11 to the other side
bahrom7893
  • bahrom7893
Square both sides: \[d^2 - 19 = (2d - 11)^2\]
bahrom7893
  • bahrom7893
Rewrite the right side as: \[d^2 - 19 = 4d^2 - 44d + 121\]
bahrom7893
  • bahrom7893
Rewrite in form of a regular quadratic equation and simplify: \[3d^2 - 44d +130 = 0\]
bahrom7893
  • bahrom7893
Can u finish solving for d?
anonymous
  • anonymous
yes, Do you have time for one more. It is similar with a cube root?
bahrom7893
  • bahrom7893
yeah
bahrom7893
  • bahrom7893
in that case u cube both sides, same method
anonymous
  • anonymous
\[\sqrt[3]{8v ^{2}-6v}+1=0\]
bahrom7893
  • bahrom7893
so move one over to the right and cube both sides to get: 8v^2 - 6v = (-1)^3 8v^2 - 6v = -1. Solve for V
anonymous
  • anonymous
I get \[8v^{2}-6v+1\]
bahrom7893
  • bahrom7893
yeah 8v^2 - 5v + 1 = 0
bahrom7893
  • bahrom7893
solve for v
anonymous
  • anonymous
thanks

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