## anonymous 5 years ago [\sqrt{d ^{2}-19} -2d + 11=0

1. bahrom7893

wait can u repost the question?

2. bahrom7893

is it the same that i answered?

3. anonymous

no i typed it wrong the first time

4. bahrom7893

So can u repost it, i still dont see the right question

5. anonymous

$\sqrt{d ^{2}-19}-2d+11=0$

6. bahrom7893

okay

7. bahrom7893

$\sqrt{d^2 - 19} = 2d - 11$ Move -2d and 11 to the other side

8. bahrom7893

Square both sides: $d^2 - 19 = (2d - 11)^2$

9. bahrom7893

Rewrite the right side as: $d^2 - 19 = 4d^2 - 44d + 121$

10. bahrom7893

Rewrite in form of a regular quadratic equation and simplify: $3d^2 - 44d +130 = 0$

11. bahrom7893

Can u finish solving for d?

12. anonymous

yes, Do you have time for one more. It is similar with a cube root?

13. bahrom7893

yeah

14. bahrom7893

in that case u cube both sides, same method

15. anonymous

$\sqrt[3]{8v ^{2}-6v}+1=0$

16. bahrom7893

so move one over to the right and cube both sides to get: 8v^2 - 6v = (-1)^3 8v^2 - 6v = -1. Solve for V

17. anonymous

I get $8v^{2}-6v+1$

18. bahrom7893

yeah 8v^2 - 5v + 1 = 0

19. bahrom7893

solve for v

20. anonymous

thanks