Systems of first order equations can sometimes be transformed into a single equation of higher order. Consider the system x 1 = −2x1 + x2, x 2 = x1 − 2x2. (a) Solve the first equation for x2 and substitute into the second equation, thereby obtaining a second order equation for x1. Solve this equation for x1 and then determine x2 also. (b) Find the solution of the given system that also satisfies the initial conditions x1(0) = 2, x2(0) = 3.

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Systems of first order equations can sometimes be transformed into a single equation of higher order. Consider the system x 1 = −2x1 + x2, x 2 = x1 − 2x2. (a) Solve the first equation for x2 and substitute into the second equation, thereby obtaining a second order equation for x1. Solve this equation for x1 and then determine x2 also. (b) Find the solution of the given system that also satisfies the initial conditions x1(0) = 2, x2(0) = 3.

Mathematics
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So you can start by taking \(x_1 = -2x_1 + x_2\) and solving it for \(x_2\). You can do this by moving the \(-2x_1\) to the right. Let me know when you've got this and we'll get the next step :)

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