A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

Systems of first order equations can sometimes be transformed into a single equation of higher order. Consider the system x 1 = −2x1 + x2, x 2 = x1 − 2x2. (a) Solve the first equation for x2 and substitute into the second equation, thereby obtaining a second order equation for x1. Solve this equation for x1 and then determine x2 also. (b) Find the solution of the given system that also satisfies the initial conditions x1(0) = 2, x2(0) = 3.

  • This Question is Closed
  1. shadowfiend
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So you can start by taking \(x_1 = -2x_1 + x_2\) and solving it for \(x_2\). You can do this by moving the \(-2x_1\) to the right. Let me know when you've got this and we'll get the next step :)

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.