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anonymous
 5 years ago
Find the arclength of:
7x^(2/3) from x=1 to x=8
anonymous
 5 years ago
Find the arclength of: 7x^(2/3) from x=1 to x=8

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have gotten up to this point: integral sq. root 9x^2/3+ 196/3 times x^1/3 dx but after that I'm stuck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f'(x)= (1/3)7x^(1/3) for arclength, you have to integrate the square root of (1+f'(x)^2, so you can square the f'(x) piece by piece... (1/3)^2 = (1/9)... (7^2)=49... [x^(1/2)]^2 = (x^(1)... put them all together... (1/9)(49*(x^1)). Add 1. Square root it. Integrate it. The hardest part will be doing the busy work of integrating. Got you started.
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