Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Find the arclength of: 7x^(2/3) from x=1 to x=8

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

I have gotten up to this point: integral sq. root 9x^2/3+ 196/3 times x^-1/3 dx but after that I'm stuck
f'(x)= (-1/3)7x^(-1/3) for arclength, you have to integrate the square root of (1+f'(x)^2, so you can square the f'(x) piece by piece... (-1/3)^2 = (1/9)... (7^2)=49... [x^(-1/2)]^2 = (x^(-1)... put them all together... (1/9)(49*(x^-1)). Add 1. Square root it. Integrate it. The hardest part will be doing the busy work of integrating. Got you started.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question