anonymous
  • anonymous
25-[2+5y-3(y+2)]=-3(2y-5)- [5(y-1)-3y+3]
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
y=7 is what I got, but I just did this in my head, so I might have messed something up.
anonymous
  • anonymous
Whoever wrote this problem had too much time to write parenthesis: y=-2
anonymous
  • anonymous
I don't know.

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anonymous
  • anonymous
I was joking can solve this easy question. Here is the answer.
anonymous
  • anonymous
Now this was _____ (not/a) joke.
anonymous
  • anonymous
Fill in the blanks.
anonymous
  • anonymous
The solution of this question is following: First we will solve LHS (left hand side) THAT IS 25-[2+5y-3(y+2)] 25-(2+5y-3y-6) 25-(-4+2y) 25+4-2y 29-2y Hence the solution of LHS is 29-2y now we will solve RHS (Right Hand Side) -3(2y-5)-[5(y-1)-3y+3] -6y+15-(5y-5-3y+3) -6y+15-(2y-2) -6y+15-2y+2 -8y+17 Hence the solution of RHS is -8y+17 So now we will put the solutions in the equation: 29-2y=-8y+17 -2y+8y=17-29 6y=-12 y=-2 Hence the solution of the given equation is -2 THANKS
anonymous
  • anonymous
Correct answer is is is is is is is is : : : : : : : : : : : : : : : : : : : : : : : : not : : : : : : : : :: : : : : : : : :: : ::

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