xvdavis
  • xvdavis
Hello, I am preparing for my Fundamentals of Engineering Exam. Here is math problem that I have below which I am having difficulty with: Given: dy(1)/dx = 2/13 (1 + 5/2x - 3/2 - 3/4k) What is the value of k such that y(1) is perpendicular to the curve y(2)=2x at x=1? I have the solution to this problem if you need to see it (Which I don't understand.) Thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathteacher1729
  • mathteacher1729
The notation you're using is a bit difficult to read. There is an "equation" button on the lower left hand corner of the text box which might make things easier. Here's my attempt to re-write your problem: \[\frac{dy_1}{dx}=\frac{2}{13}(1+\frac{5}{2}x-\frac{3}{2}-\frac{3}{4}k\] Find \[k\] such that \[y_1\] is perpendicular to \[y_2=2x\] when \[x = 1\] ?
mathteacher1729
  • mathteacher1729
Sorry, should be \frac{dy_1}{dx}=\frac{2}{13}(1+\frac{5}{2}x-\frac{3}{2}-\frac{3}{4}k) I forgot to close the parenthesis.
mathteacher1729
  • mathteacher1729
\[\frac{dy_1}{dx}=\frac{2}{13}(1+\frac{5}{2}x-\frac{3}{2}-\frac{3}{4}k\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathteacher1729
  • mathteacher1729
Grrrrr! \[\frac{dy_1}{dx}=\frac{2}{13}(1+\frac{5}{2}x-\frac{3}{2}-\frac{3}{4}k)\]
anonymous
  • anonymous
let value of dy1/dx at x=1 be c. c x dy2/dx =-1 2c=-1 solve the equation
anonymous
  • anonymous
dy1/dx at x=1 means substitute value of x as 1 in dy1/dx
anonymous
  • anonymous
as the two curves are perpendicular at the givn point the product of their slopes should be -1
xvdavis
  • xvdavis
Thank you.

Looking for something else?

Not the answer you are looking for? Search for more explanations.