Hello, I am preparing for my Fundamentals of Engineering Exam. Here is math problem that I have below which I am having difficulty with:
Given: dy(1)/dx = 2/13 (1 + 5/2x - 3/2 - 3/4k)
What is the value of k such that y(1) is perpendicular to the curve y(2)=2x at x=1?
I have the solution to this problem if you need to see it (Which I don't understand.)
Thanks!

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\[\frac{dy_1}{dx}=\frac{2}{13}(1+\frac{5}{2}x-\frac{3}{2}-\frac{3}{4}k\]

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