## anonymous 5 years ago Teri got a 44 and 72 on her 1st 2 algebra tests. In order to pass the class with a 60%, what is the lowest grade she can get on the remaining test????

Assuming that the entire class grade is just the average of the three tests (a poorly designed grading scheme if you ask me!) then you have to solve the following: $\frac{44+72+x}{300}=\frac{60}{100}$ This is not so bad because you can add 44 and 72 because they are in the numerator of the left fraction... $\frac{116+x}{300}=\frac{60}{100}$ Now reduce that 60/100 on the right hand side: Divide by 10 $\frac{116+x}{300}=\frac{6}{10}$ Divide by 2 $\frac{116+x}{300}=\frac{3}{5}$ Ok, so from here we do some cross multiplication to solve for x. :) Hope this helps!