A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Inverse of Log base 4 of x
anonymous
 5 years ago
Inverse of Log base 4 of x

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*gasp i was thinking that! well there's one i got right on the test..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, try this one! Log base 2 of x + 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is y = 2^x  3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you show me how you did that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0darn..that means i probably got that wrong in the test. :\

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okie! So it's: y = Log base e of x + 3, NOT (x+3) So it's 2^y = x + 3 There fore, 2^x  3 = y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0id remember if i got that right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x ^ y = 3x Inverse = x^x = 3y, so it's y = (x^x) / 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, I'll change base x to base 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so that you won't be confuse with which x to switch

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02^y or x^y in the original = 3x Inverse = 2^x original x^x = 3y so divide both side by 3 to get y y = (2^x)/3 or (x^x)/3 in the original
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.