Inverse of Log base 4 of x

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Inverse of Log base 4 of x

Mathematics
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y=4^x\[f(x)=4^x\] ?
Yes Perto! xD
*gasp i was thinking that! well there's one i got right on the test..

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Other answers:

Now, try this one! Log base 2 of x + 3
the inverse of that?
yesh!
f(x)= 2^(x+3)
?
Nope!
D:
f(x)= 2^x ?
wait a sec!
wait lemme see!
where's hanh?
The answer is y = 2^x - 3
why minus?
can you show me how you did that
cuz its the inverse
darn..that means i probably got that wrong in the test. :\
Okie! So it's: y = Log base e of x + 3, NOT (x+3) So it's 2^y = x + 3 There fore, 2^x - 3 = y
id remember if i got that right
base 2*
next problem
Log base x of 3x
thats wierd
x ^ y = 3x Inverse = x^x = 3y, so it's y = (x^x) / 3
thats wierd
okay, I'll change base x to base 2
why?
so that you won't be confuse with which x to switch
2^y or x^y in the original = 3x Inverse = 2^x original x^x = 3y so divide both side by 3 to get y y = (2^x)/3 or (x^x)/3 in the original

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