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anonymous
 5 years ago
A triangular region has a perimeter of 66 meters. The first side is twothirds of the second side. The third side is 14 meters shorter than the second side. What are the lengths of the three sides of the triangular region?
anonymous
 5 years ago
A triangular region has a perimeter of 66 meters. The first side is twothirds of the second side. The third side is 14 meters shorter than the second side. What are the lengths of the three sides of the triangular region?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let second side = x meter, first side = 2x/3 meter and third side = x14 sum of all sides i.e perimeter x +2x/3 + x14 = 66 => 2x+2x/3 =80 =>8x/3 =80 => x = 30 so, first side = 20 meters, second side = 30 meters third side = 16 meters

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get the 80?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you eliminate the fraction? 2/3x I thought you should multiply both sides of the equation by the least common denominator. Thanks for the explanation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x + \frac{2}{3}x + (x14) = 66\] You can add the like terms, so you get\[x + \frac{2}{3}x + x = \frac{3}{3}x + \frac{2}{3}x + \frac{3}{3}x = \frac{3+2+3}{3}x = \frac{8}{3}x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{8}{3}x  14 = 66 \ \ , \frac{8}{3}x = 80 \ \ , 8x = 240 \ \ , x = 30\] Then solve for the other two sides.
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