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y = Ln(1+x)
e^y = e^[Ln(1+x)]
e^y = 1 + x

x = e^y - 1

Close, but no Bahroom...^^

No? what's the answer, i think its just in a different format.

It should be in term of y! xD

wait what's in terms of y?

it is in terms of y; x = f(y)

It's y = Ln(x+1)
and I want the inverse in term of y = .....

No, the answer is:
x = e^y + 1

Nah...It's
y = e^x -1

okay i think i get it

notice the hesitance i have

why are you looking at this hanh?