• anonymous
How do I solve w(w)-24w+144=0 for the polynomial roots?
  • chestercat
I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this
and thousands of other questions

  • anonymous
The roots of the equation are the x-intercepts. What we are being asked is to find the values of these x intercepts for this quadratic equation (which can have 0, 1 or 2 roots depending on the parabola position). So, w^2 - 24w + 144 = 0 We can use factoring a perfect trinomial. We want to look numbers that multiply to 144 that add up to 12 (this can include negative numbers). (w -12)(w -12) ---- these are the factors and since we are asked to solve we must find the respective solutions. But, since these are the same factors, we only need to solve for one. w - 12 = 0 w = 12 ---- ANSWER To double check plug 12 for w into the original equation and see if the LHS = RHS or 0 = 0.
  • anonymous
Sorry I meant to the two numbers that multiply to 144 that add up to -24. My bad :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.