A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do I solve w(w)24w+144=0 for the polynomial roots?
anonymous
 5 years ago
How do I solve w(w)24w+144=0 for the polynomial roots?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The roots of the equation are the xintercepts. What we are being asked is to find the values of these x intercepts for this quadratic equation (which can have 0, 1 or 2 roots depending on the parabola position). So, w^2  24w + 144 = 0 We can use factoring a perfect trinomial. We want to look numbers that multiply to 144 that add up to 12 (this can include negative numbers). (w 12)(w 12)  these are the factors and since we are asked to solve we must find the respective solutions. But, since these are the same factors, we only need to solve for one. w  12 = 0 w = 12  ANSWER To double check plug 12 for w into the original equation and see if the LHS = RHS or 0 = 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry I meant to the two numbers that multiply to 144 that add up to 24. My bad :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.