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anonymous
 5 years ago
implicit differentiation: sin((x^2)(y^2))=x
anonymous
 5 years ago
implicit differentiation: sin((x^2)(y^2))=x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this sin [ x^2y^2] = x ? or (sin x^2 ) y^2 = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0jkwon, let me answer it. i got this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sin(x^2y^2)=x \] \[\cos(x^2y^2)(2xy^2+x^2(2y)(y')=1\] \[2xy^2+x^2(2y)y'=1/[\cos(x^2y^2)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you use latex?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh I only did half of it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you explain chain rule?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you type latex like type integral x dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you treat the problem like an onion. You do the outer layer and then you go to the second layer, then the third. So the outer layer is the cosine, and the inner layer is the x^2y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oops i mean sine is the outer layer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i gotcha. so you just derive each in parts depending on parenthesis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0remember the inside is the product

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha, jk i think you have this in the bud

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well im a math major, so whatever needs help, I like to solve it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats a non archimedean ordered field?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you ask that in a separate question? you're distracting him from helping me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so yeah, the product rule for the x^2y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0notgoodatmath, dont speak unless told to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have 15 fans, i have solved a hundred math problems

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just want help with this problem, and you aren't helping me. Your're doing the opposite actually.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey cantorset, use the equation editor in the lower left hand side of the reply box

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok did you see my comment on n^n / n!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh did not check heh, will do so

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont see that as an argument what you did to show it converges
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