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anonymous

  • 5 years ago

implicit differentiation: sin((x^2)(y^2))=x

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  1. anonymous
    • 5 years ago
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    ok

  2. anonymous
    • 5 years ago
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    is this sin [ x^2y^2] = x ? or (sin x^2 ) y^2 = x

  3. anonymous
    • 5 years ago
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    first one

  4. anonymous
    • 5 years ago
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    ok

  5. anonymous
    • 5 years ago
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    please make me fan

  6. anonymous
    • 5 years ago
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    make you fan?

  7. anonymous
    • 5 years ago
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    jkwon, let me answer it. i got this

  8. anonymous
    • 5 years ago
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    \[\sin(x^2y^2)=x \] \[\cos(x^2y^2)(2xy^2+x^2(2y)(y')=1\] \[2xy^2+x^2(2y)y'=1/[\cos(x^2y^2)]\]

  9. anonymous
    • 5 years ago
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    grrrr

  10. anonymous
    • 5 years ago
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    oh ok

  11. anonymous
    • 5 years ago
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    oh wow

  12. anonymous
    • 5 years ago
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    how do you use latex?

  13. anonymous
    • 5 years ago
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    Oh I only did half of it

  14. anonymous
    • 5 years ago
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    could you explain chain rule?

  15. anonymous
    • 5 years ago
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    sure

  16. anonymous
    • 5 years ago
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    how do you type latex like type integral x dx

  17. anonymous
    • 5 years ago
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    So you treat the problem like an onion. You do the outer layer and then you go to the second layer, then the third. So the outer layer is the cosine, and the inner layer is the x^2y^2

  18. anonymous
    • 5 years ago
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    So then....

  19. anonymous
    • 5 years ago
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    Oops i mean sine is the outer layer

  20. anonymous
    • 5 years ago
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    yeah i gotcha. so you just derive each in parts depending on parenthesis

  21. anonymous
    • 5 years ago
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    pretty much yeah ^^

  22. anonymous
    • 5 years ago
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    remember the inside is the product

  23. anonymous
    • 5 years ago
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    haha, jk i think you have this in the bud

  24. anonymous
    • 5 years ago
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    huh?

  25. anonymous
    • 5 years ago
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    nvm

  26. anonymous
    • 5 years ago
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    well im a math major, so whatever needs help, I like to solve it

  27. anonymous
    • 5 years ago
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    whats a non archimedean ordered field?

  28. anonymous
    • 5 years ago
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    can you ask that in a separate question? you're distracting him from helping me

  29. anonymous
    • 5 years ago
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    so yeah, the product rule for the x^2y^2

  30. anonymous
    • 5 years ago
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    yuppp

  31. anonymous
    • 5 years ago
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    notgoodatmath, dont speak unless told to

  32. anonymous
    • 5 years ago
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    i have 15 fans, i have solved a hundred math problems

  33. anonymous
    • 5 years ago
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    what is Y'?

  34. anonymous
    • 5 years ago
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    I just want help with this problem, and you aren't helping me. Your're doing the opposite actually.

  35. sandra
    • 5 years ago
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    hey cantorset, use the equation editor in the lower left hand side of the reply box

  36. sandra
    • 5 years ago
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    for latex

  37. anonymous
    • 5 years ago
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    oh ok did you see my comment on n^n / n!

  38. sandra
    • 5 years ago
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    oh did not check heh, will do so

  39. anonymous
    • 5 years ago
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    i dont see that as an argument what you did to show it converges

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spraguer (Moderator)
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