At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I'm assuming you mean 5+3(1+2(2x-3)) = 6(x+5)

this is another case where you need to distribute

start with the right side, what is 6(x+5) ?

yes

6x+30?

yep!

ok now start from the inside out on the left hand side

do u always start with the right side

so what is 2(2x-3)

well, I think generally start from inside out

as in inner-most thing that needs to be expanded

4x-6

ok great, so to recap, so far we have:
5 + 3(1 + 4x - 6) = 6x + 30

gotcha

5x-6 or do u break that down further

well, that's not correct

you can't combine 1 and 4x, since you don't know what 4x

but you can combine 1 and -6

(by adding them)

-5

if it had been (1x +4x -6) you would have been correct, since the 1 and 4 are both x's

right so the middle is now -5 + 4x, or 4x - 5

so now you have : 5 + 3(4x - 5) = 6x + 30

what is your next step?

5+12x-15=6x+30

great =)

so can you combine anything on the left side?

5 and 15 which is -10

yep =), so now what do you have?

is it 12x-10=6x+30

exactly

the reason that's powerful is because it allows you to eventually get x all by itself

so let's say you wanted to get 12x by itself on the left hand side

what could you add to both sides to make that happen?

add 10

yep, and what do you get if you add 10 to both sides

12x=6x+40

so what could you subtract from both sides, to get all of the x's in one place?

would u minus 6x

exactly, and then what you get?

6x=40 then i divided by 6 both sides

yep!

good work

6.6?

yeah, or you could write it as a fraction

so x = 40/6

and that can be reduced if you divide both top and bottom by 2

so x = 20/3

so now that you think x = 20/3

thank u so much i think im getting it sum what lol

you stick it back into the original equation (or just use 6.666666 to check in your calculator)

and if the equation is true, then you know you got it right

so for these types of problems, try expanding everything out first

and then just get the value for one x by dividing

after a while, you'll start seeing some shortcuts if they're there

for example, if you had 3(x+3) = 12

you wouldn't *have* to expand first

you could just divide both sides by 3

to get x+3 = 4

and then subtract 3 from both sides to get x=1

but seeing that will come with practice

good luck!

oh ok thanks a bunch !!!!

yep np