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integral of (x^2+5x+6)/(x^2+2x+1) partial fraction form please help!

Mathematics
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ok so you see that the denominator is \[x^2+2x+1\] So you should first factor the denominator. Then you get (x+1)^2 Then finally: \[(x^2+5x+6)/(x+1)^2= A/(x+1) + B/(x+1)\] \[\] You you think you can do the rest?
\[A/(x+1)+B/(x+1)\]
oops...keeping doing typos

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Other answers:

\[A/(x+1)+B(x+1)^2\]
how does it get from (x^2+5x+6)/(x^2+2x+1) to 1+ (3x+5)/(x^2+2x+1)
thank you for your help btw
I didn't get 1+(3x+5).... Just factor the bottom and put the coefficients like i did above.

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