anonymous
  • anonymous
integral of (x^2+5x+6)/(x^2+2x+1) partial fraction form please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
ok so you see that the denominator is \[x^2+2x+1\] So you should first factor the denominator. Then you get (x+1)^2 Then finally: \[(x^2+5x+6)/(x+1)^2= A/(x+1) + B/(x+1)\] \[\] You you think you can do the rest?
anonymous
  • anonymous
\[A/(x+1)+B/(x+1)\]
anonymous
  • anonymous
oops...keeping doing typos

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anonymous
  • anonymous
\[A/(x+1)+B(x+1)^2\]
anonymous
  • anonymous
how does it get from (x^2+5x+6)/(x^2+2x+1) to 1+ (3x+5)/(x^2+2x+1)
anonymous
  • anonymous
thank you for your help btw
anonymous
  • anonymous
I didn't get 1+(3x+5).... Just factor the bottom and put the coefficients like i did above.

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