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anonymous

  • 5 years ago

integral of (x^2+5x+6)/(x^2+2x+1) partial fraction form please help!

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  1. anonymous
    • 5 years ago
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    ok so you see that the denominator is \[x^2+2x+1\] So you should first factor the denominator. Then you get (x+1)^2 Then finally: \[(x^2+5x+6)/(x+1)^2= A/(x+1) + B/(x+1)\] \[\] You you think you can do the rest?

  2. anonymous
    • 5 years ago
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    \[A/(x+1)+B/(x+1)\]

  3. anonymous
    • 5 years ago
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    oops...keeping doing typos

  4. anonymous
    • 5 years ago
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    \[A/(x+1)+B(x+1)^2\]

  5. anonymous
    • 5 years ago
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    how does it get from (x^2+5x+6)/(x^2+2x+1) to 1+ (3x+5)/(x^2+2x+1)

  6. anonymous
    • 5 years ago
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    thank you for your help btw

  7. anonymous
    • 5 years ago
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    I didn't get 1+(3x+5).... Just factor the bottom and put the coefficients like i did above.

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