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anonymous
 5 years ago
heres another one, write an equation for the line that is perpendicular to the given line and that contains the given point. 3x + 2y = 10; (9,2)
anonymous
 5 years ago
heres another one, write an equation for the line that is perpendicular to the given line and that contains the given point. 3x + 2y = 10; (9,2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Perpendicular is a different story. If the orginal line have the slope of 3. Then a new perpendicular line must have a slope of the negative reciprocal. This means that the slope must be (1/3).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is the slope of the line 3x + 2y = 10? If you put it into slopeintercept form, you'll see that y = (3/2) x  5. So the slope is 3/2. The slope of a perpendicular line to 3x + 2y = 10 must then have slope 2/3 (the negative reciprocal of 3/2). So then we want this perpendicular line to pass through (9, 2). So we can use “pointslope” form of a line: y – y1 = m*(x – x1). So y – (2) = (2/3) * (x – (9)). Simplify to get the equation of the line which is perpendicular to your first line and going through the point (9, 2).
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