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anonymous
 5 years ago
solve: 3x/2+1/x=3x/4
anonymous
 5 years ago
solve: 3x/2+1/x=3x/4

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shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0The first move would be to multiply through by x: 3x^2 / 2 + 1 = 3x^2 / 4 Then multiply through by 4: 6x^2 + 4 = 3x^2 Can you solve that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean multiply through by x?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0We multiply both sides by x, so that we can get x out of the denominator in 1 / x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0arent you looking for a common denominator of 2x though?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Hm? No, you can just multiply both sides by x, and that'll cancel the x out in the denominator on the left, and make the other two xes x^2s instead.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand what your saying

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0The easiest way to solve an equation like this is to make sure there is no x in any denominators.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so multiply everything by x/x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont really understand i thought you would multiply everything by 2x to get a common denominator and then add the left side?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are multiple ways to approach this problem. finding common denominator for LHS of equation and cross multiplying is also another way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok can you show me steps on how to solve this equation please

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0You don't have to multiply by x/x, you can just multiply by x. For example: 5 = 5 x*5 = x*5 5x = 5x So the equation is still valid. In this case: \[\frac{3x}{2}+\frac{1}{x} = \frac{3x}{4}\] \[x\left(\frac{3x}{2}+\frac{1}{x}\right) = x\frac{3x}{4}\] \[\frac{x\cdot 3x}{2} + \frac{x\cdot 1}{x} = \frac{x\cdot 3x}{4}\] \[\frac{3x^2}{2} + \frac{x}{x} = \frac{3x^2}{4}\] \[\frac{3x^2}{2} + 1 = \frac{3x^2}{4}\] (And Minhee is correct about there being multiple approaches; just trying to explain mine. Have to go now though, sorry.)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can multiply both sides of equations by x, 2x or 4x. All of which should give you the same answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you i got the answer..can you take a look at my other problems?
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