anonymous 5 years ago solve: 3x/2+1/x=3x/4

The first move would be to multiply through by x: 3x^2 / 2 + 1 = 3x^2 / 4 Then multiply through by 4: 6x^2 + 4 = 3x^2 Can you solve that?

2. anonymous

what do you mean multiply through by x?

We multiply both sides by x, so that we can get x out of the denominator in 1 / x.

4. anonymous

arent you looking for a common denominator of 2x though?

Hm? No, you can just multiply both sides by x, and that'll cancel the x out in the denominator on the left, and make the other two x-es x^2s instead.

6. anonymous

i dont understand what your saying

The easiest way to solve an equation like this is to make sure there is no x in any denominators.

8. anonymous

ok so multiply everything by x/x?

9. anonymous

i dont really understand i thought you would multiply everything by 2x to get a common denominator and then add the left side?

10. anonymous

there are multiple ways to approach this problem. finding common denominator for LHS of equation and cross multiplying is also another way.

11. anonymous

ok can you show me steps on how to solve this equation please

You don't have to multiply by x/x, you can just multiply by x. For example: 5 = 5 x*5 = x*5 5x = 5x So the equation is still valid. In this case: $\frac{3x}{2}+\frac{1}{x} = \frac{3x}{4}$ $x\left(\frac{3x}{2}+\frac{1}{x}\right) = x\frac{3x}{4}$ $\frac{x\cdot 3x}{2} + \frac{x\cdot 1}{x} = \frac{x\cdot 3x}{4}$ $\frac{3x^2}{2} + \frac{x}{x} = \frac{3x^2}{4}$ $\frac{3x^2}{2} + 1 = \frac{3x^2}{4}$ (And Min-hee is correct about there being multiple approaches; just trying to explain mine. Have to go now though, sorry.)

13. anonymous

you can multiply both sides of equations by x, 2x or 4x. All of which should give you the same answer

14. anonymous

thank you i got the answer..can you take a look at my other problems?