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anonymous

  • 5 years ago

5X +3Y = 2 and 6X and 4Y=9 I can not get them to equal

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  1. anonymous
    • 5 years ago
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    yes.

  2. anonymous
    • 5 years ago
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    but for realz i don't understand what you're trying to say.

  3. anonymous
    • 5 years ago
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    just the "and 6X and"

  4. anonymous
    • 5 years ago
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    I have to put numbers in the x and y to get them to equal 2 for the first prob and 9 on the second prob thanks

  5. anonymous
    • 5 years ago
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    I should have put in a + sign for and sorry

  6. anonymous
    • 5 years ago
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    igggghhht so you got: 5x + 3y = 2 and 6x + 4y = 9 well one thing you can do is to get rid of one coefficient, let's say the y one. mutliply the first equation by 4, and the second one by 3, then substract them: 20x + 12y = 8 - 18x + 12y = 27 = 2x = -19 x = -19/2 plug that in ant of the initial equations to find y

  7. anonymous
    • 5 years ago
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    I understand what you did here..thank you very much. My student is saying thank you also. How do you do it for Y? Plug in the X answer for Y and solve?

  8. anonymous
    • 5 years ago
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    exactly, you can plug it in the first or second initial equation and it should give you the same answer

  9. anonymous
    • 5 years ago
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    we get 190 =8 ..does that make sense? 23.75 = y ..does that sound right?

  10. anonymous
    • 5 years ago
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    we get two different answers, 23.75 and 171

  11. anonymous
    • 5 years ago
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    oops she got 23.75 for first equation and 6.3 for the second equation

  12. anonymous
    • 5 years ago
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    ok well if we have x = -19/2: 5x + 3y =2 -95/2 + 3y = 2 y = (2 + 95/2)/3 = 16.5 6x + 4y = 9 -57 + 4y = 9 4y = 66 y = 66/4 = 16.5

  13. anonymous
    • 5 years ago
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    You are really good. Mariah says thanks and what about 2x +5y =16 and 4x +7y=23

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