anonymous
  • anonymous
alright i dont know how to do this. x=16-4x 3x+4y=8
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
do you know it?
anonymous
  • anonymous
first make x at left had side x+4x= 16 5x = 16 x = 16/5 then 3x+4y =8 4y =8 -3x y = 1/4(8 - 3x) insert x y = 1/4(8 - 3(16/5)) y =-2/5
anonymous
  • anonymous
but my teacher says it shouldnt be a fraction

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anonymous
  • anonymous
you type the question wrong
anonymous
  • anonymous
well thats how it is on my paper
anonymous
  • anonymous
for : x=16-4y; 3x+4y=8 x =5 and y = 11/4
anonymous
  • anonymous
okay thanks:)
anonymous
  • anonymous
how do you solve it?
anonymous
  • anonymous
like wrok it out please?
anonymous
  • anonymous
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anonymous
  • anonymous
x=16-4y as first equation, 3x+4y=8 change to 3x=8-4y then to x=1/3(8-4y) and take as second equation first equation = second equation as x = x 16-4y =1/3(8-4y) 3(16-4y)= 8-4y 48-12y = 8 -4y 48-8 = 12y -4y 40 = 8y 5 = y then insert y=5 into x=16-4y x =16-4(5) x= -4 then x=-4 and y=5
anonymous
  • anonymous
sorry for miscalculating b4
anonymous
  • anonymous
its okay i was just confused

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