anonymous
  • anonymous
I have a problem with differential equations. "Solve the initial value problem: dy/dx +2y = 4x, y(0) = 2" If you can help, even if it's only pointing me in the right direction for what process I need to use, that'd be great.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
This is called the method of integrating factors. The idea is that we'd like to rewrite the Left Hand Side of y' +f(x) y = g(x) as the derivative of a product of y with some other function h(x). Notice that the derivative of y(x)h(x) is y’h + h’y. This kind of looks like y’ + f(x)*y. But to make that look even more like y’h + h’y, we can multiply y’ + f(x)*y by the function h (to be determined) to get h[y’ + f(x)*y] = y’h + (h*f)*y. So what should our function h be ? Our h should satisfy (hf) = h’ to match the expressions y’h + (hf)*y and y’h + h’y. Solving hf = h’ is easy since its separable. In this case, if we have y’ + 2y = x^2 So we’d like to multiply both sides of the equation by some h(x). And that h(x) should satisfy h*(2) = h’. Solving this gives h(x) = e^(2x) Then multiply both sides of y’ + 2y = 4x by e^(2x), recognize that the Left Hand Side is the derivative of y*e^(2x), and continue from there. Once you get the general solution, plug in the initial values to get the specified solution.
anonymous
  • anonymous
Thanks a lot verifry.
anonymous
  • anonymous
I had some notes that showed it, but the process was completely lost on me. A massive help.

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anonymous
  • anonymous
No problem.

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