A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Verify The Identity
Cos(x)+Sin(x)Tan(x)=Sec(x)
Can someone please help explain to me how to verify an identity?
anonymous
 5 years ago
Verify The Identity Cos(x)+Sin(x)Tan(x)=Sec(x) Can someone please help explain to me how to verify an identity?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try drawing a triangle and label the ratios and go from there....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok.. I guess I'm confused by what ratios? No numbers were given. I know you probably would start with the left side of this equation (maybe divide each side by tan(x)?)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use this, and create your ratios...Example Sin=b/c http://3.bp.blogspot.com/_kjNvt_oqTsE/TORcXMO_H6I/AAAAAAAAACo/CbLIh4wjhaI/s1600/Image289.gif

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put it in those terms and it should be easier for you to prove...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Proving a proof cannot be done using what is given, it must be changed to new terms...Just like the definition of a word can't include the word....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does it matter where I put each term?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put them in the order of the identity...So, Cosx becomes (a/c) etc...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I have cosx=a/c sinx=b/c and tanx= c/?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the tangent is what? Its the opposite side/adjacent side... (b/a)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So...(a/c)+(b/c)(b/a) and solve...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OHHH ok! and I want it to equal secx which is equal to what? a/b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OHHH ok! and I want it to equal secx which is equal to what? a/b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have confused you, and I'm sorry...You need to see that Tangent equals (sin/cos) and make that substitution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Once you see that, then the fractions become easier to work, because they are impossible to work without that substitution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so i understand that now...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Completely ignore the answer Secant side of the equation, and solve the fractional problem...and you'll determine what secant is in terms of fractions, which is what they want....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, basically, this... sin x tan x + cos x = sin x (sin x / cos x) + cos x = ( sin^2(x) / cos x ) + cos x = [ sin^2(x) + cos^2(x) ] / cos x = 1 / cos x = sec x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright so I was close on my paper... I think I just mixed up the terms. Therefore this is an identity. Thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok one more Question...does theta basically resemble the x in the previous problem?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.