## anonymous 5 years ago what is the solution to the system of equations shown below? 2x-y+3z=8 x-6y-z=0 -6x+3y-9z=24 please someone help!

1. anonymous

Set up a matrix: 2 -1 3 | 8 1 -6 -1 | 0 -6 3 -9 | 24 Bring it to reduced row echelon form (no nonzero terms except leading 1s) You'll have x, y, z.

2. anonymous

ugh im still confused lol, how would i set it up though?

3. anonymous

Take the coefficients of each equation and put them in a matrix. Then perform row operations (ex. $R_3 \rightarrow R_2 - R_1$)

4. anonymous

okay thank uu