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anonymous

  • 5 years ago

what is the solution to the system of equations shown below? 2x-y+3z=8 x-6y-z=0 -6x+3y-9z=24 please someone help!

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  1. anonymous
    • 5 years ago
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    Set up a matrix: 2 -1 3 | 8 1 -6 -1 | 0 -6 3 -9 | 24 Bring it to reduced row echelon form (no nonzero terms except leading 1s) You'll have x, y, z.

  2. anonymous
    • 5 years ago
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    ugh im still confused lol, how would i set it up though?

  3. anonymous
    • 5 years ago
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    Take the coefficients of each equation and put them in a matrix. Then perform row operations (ex. \[R_3 \rightarrow R_2 - R_1\])

  4. anonymous
    • 5 years ago
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    okay thank uu

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