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anonymous
 5 years ago
In 1920, the record for a certain race was 45.7 sec. In 1970, it was 44.7 sec. Let R(t) = the record in the race and t= the number of years since 1920.
a Find the linear function that fits the data
b Use the function in (a) to predict the record for 2003 and in 2006
c Find the year when the record will be 43.94 sec.
anonymous
 5 years ago
In 1920, the record for a certain race was 45.7 sec. In 1970, it was 44.7 sec. Let R(t) = the record in the race and t= the number of years since 1920. a Find the linear function that fits the data b Use the function in (a) to predict the record for 2003 and in 2006 c Find the year when the record will be 43.94 sec.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a) Since the question asks for a linear function that gives us a hint that we want a straight line (y=mx+b). So you first need to find the slope: m=(y2y1)/(x2x1)= (44.745.7)/(500)=1/50=0.02 Then we need to find our yintercept (b), so we will use x=0 and y=50 which will represent the 1920 record: 50=0.02(0)+b 50=b Therefore, your linear function will be y=0.02x+50 b) For the 2003 (20031920=83 years since 1920), plug in 83 for x. Likewise for the 2006 record plug in 86 for x. c) Set y=43.94. So your equation looks like this: 43.94=0.02x+50 Then solve for x: (43.9450)/(0.02)=x
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