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anonymous

  • 5 years ago

solve for x: 4^(3x+5)=16

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  1. anonymous
    • 5 years ago
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    x = -1

  2. anonymous
    • 5 years ago
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    how do you do it though??

  3. anonymous
    • 5 years ago
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    it's very easy..........

  4. anonymous
    • 5 years ago
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    can u teach me?

  5. anonymous
    • 5 years ago
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    yes, off course , free of cost........

  6. anonymous
    • 5 years ago
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    that's why i m here ......

  7. anonymous
    • 5 years ago
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    lol dont be annoying

  8. anonymous
    • 5 years ago
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    i m not joking..........

  9. anonymous
    • 5 years ago
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    moving on..

  10. anonymous
    • 5 years ago
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    you can just set the equation in the exponent = to 2... becuase u know that 4^2 is 16, so 3x+5=2

  11. bahrom7893
    • 5 years ago
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    Step by step: 4^(3x+5)=16 Rewrite 16 as 4^2: 4^(3x+5) = 4^2 Take Ln of both sides: Ln[4^(3x+5)] = Ln[4^2] Remember the property: LnA^b = b*LnA, so: 3x+5 = 2; 3x = -3; x = -1

  12. anonymous
    • 5 years ago
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    sorry, for late reply, due tp connection problem..

  13. anonymous
    • 5 years ago
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    Here step by step: http://www.yourfreetutor.com/index.php?option=com_content&view=article&id=99&Itemid=226

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