anonymous
  • anonymous
solve for x: 4^(3x+5)=16
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
x = -1
anonymous
  • anonymous
how do you do it though??
anonymous
  • anonymous
it's very easy..........

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anonymous
  • anonymous
can u teach me?
anonymous
  • anonymous
yes, off course , free of cost........
anonymous
  • anonymous
that's why i m here ......
anonymous
  • anonymous
lol dont be annoying
anonymous
  • anonymous
i m not joking..........
anonymous
  • anonymous
moving on..
anonymous
  • anonymous
you can just set the equation in the exponent = to 2... becuase u know that 4^2 is 16, so 3x+5=2
bahrom7893
  • bahrom7893
Step by step: 4^(3x+5)=16 Rewrite 16 as 4^2: 4^(3x+5) = 4^2 Take Ln of both sides: Ln[4^(3x+5)] = Ln[4^2] Remember the property: LnA^b = b*LnA, so: 3x+5 = 2; 3x = -3; x = -1
anonymous
  • anonymous
sorry, for late reply, due tp connection problem..
anonymous
  • anonymous
Here step by step: http://www.yourfreetutor.com/index.php?option=com_content&view=article&id=99&Itemid=226

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