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anonymous

  • 5 years ago

Segment Addition: Can someone help me solve this problem? In a rowing race, the distance between the teams in first and second place is 5.7 meters. The distance between the teams in second and third place is one-third that distance. How much farther ahead is the team in first place than the team in third?

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  1. bahrom7893
    • 5 years ago
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    Distance b/n 1st and 2nd: 5.7 Distance b/n 2nd and 3rd is 1/3 that, so : 5.7 * (1/3) = 1.9

  2. bahrom7893
    • 5 years ago
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    Total distance: 5.7 + 1.9 = 13.3 <- Dis b/n 1 and 3

  3. bahrom7893
    • 5 years ago
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    fan me if i helped, please

  4. anonymous
    • 5 years ago
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    okay thanks! can you please explain to me how you got this answer? : )

  5. bahrom7893
    • 5 years ago
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    Well you have given: Distance b/n 1st and 2nd is 5.7 and distance between 2nd and 3rd is 1/3 of 5.7, which means divide 5.7 by 3

  6. bahrom7893
    • 5 years ago
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    so distance b/n 2nd and 3rd is 5.7/3 = 1.9

  7. anonymous
    • 5 years ago
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    so you multiply then divide?

  8. anonymous
    • 5 years ago
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    or just divide?

  9. bahrom7893
    • 5 years ago
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    So from 1 to 2 there is 5.7 and from 2 to 3 there is 1.9. Which means from 1 to 3 there is 5.7+1.9 = 7.6

  10. bahrom7893
    • 5 years ago
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    no u just divide, and sorry my previous answer was a typo, its not 13.3, the answer is 7.6

  11. anonymous
    • 5 years ago
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    hmm im totally confused : /

  12. anonymous
    • 5 years ago
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    is this the first step --> 5.7 * (1/3) = 1.9 then you would add 5.7+1.9= 7.6?

  13. anonymous
    • 5 years ago
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    & you get 7.6 as your answer?

  14. bahrom7893
    • 5 years ago
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    yes

  15. anonymous
    • 5 years ago
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    thank youuu! : )

  16. bahrom7893
    • 5 years ago
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    np

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