Segment Addition: Can someone help me solve this problem? In a rowing race, the distance between the teams in first and second place is 5.7 meters. The distance between the teams in second and third place is one-third that
distance. How much farther ahead is the team in first place than the team in third?

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Distance b/n 1st and 2nd: 5.7
Distance b/n 2nd and 3rd is 1/3 that, so : 5.7 * (1/3) = 1.9

Total distance:
5.7 + 1.9 = 13.3 <- Dis b/n 1 and 3

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